Normality = Molarity x n
n = 2 ( corresponding to the two Na+ ions)
M = N / n = 1 / 2 = 0.5 =%26gt; 0.5 moles / 1L of solution
Molar mass = 106 g/mol
0.5 mol x 106 g/mol = 53 g
we take 53 g of the salt and we add enought water to reach the volume of 1 L
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